24t^2+48t-360=0

Solution for 24t^2+48t-360=0 equation:

24t^2+48t-360=0

a = 24; b = 48; c = -360;
Δ = b2-4ac
Δ = 482-4·24·(-360)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-192}{2*24}=\frac{-240}{48}
=-5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+192}{2*24}=\frac{144}{48}
=3
$